How does acceleration work in the centroid control system?
Posted: Sat May 25, 2024 2:31 am
I recently saw a post referencing acceleration and am a bit confused about how centroid handles acceleration and how setting acceleration time actually works.
The setup manual states that the acceleration time sets the time to achieve maximum velocity. Let’s say I have a machine that can go up to 100ipm. With an accel time if .5 sec.
I assume this means that if I do a move at 100 ipm, the machine will accelerate to 100 ipm in .5 sec, or a rate of 200ipm/sec.
If I do a move at 50 ipm, I assume that the acceleration rate of the machine is still 200 ipm/sec, and that it reached the target velocity in .25 sec. Is this correct?
I saw a post recently where it seemed to
Imply that all accelerations would take .5 sec, so an acceleration to 10 ipm would still take .5 seconds. It seems this approach would leave a lot of performance in the table because the acceleration would need to be set based on the limitation of the motor and machine frame during rapid moves, and be performing at a fraction of available acceleration at lower velocities. Based on that, I’m thinking I may have misunderstood that post.
Thanks.
The setup manual states that the acceleration time sets the time to achieve maximum velocity. Let’s say I have a machine that can go up to 100ipm. With an accel time if .5 sec.
I assume this means that if I do a move at 100 ipm, the machine will accelerate to 100 ipm in .5 sec, or a rate of 200ipm/sec.
If I do a move at 50 ipm, I assume that the acceleration rate of the machine is still 200 ipm/sec, and that it reached the target velocity in .25 sec. Is this correct?
I saw a post recently where it seemed to
Imply that all accelerations would take .5 sec, so an acceleration to 10 ipm would still take .5 seconds. It seems this approach would leave a lot of performance in the table because the acceleration would need to be set based on the limitation of the motor and machine frame during rapid moves, and be performing at a fraction of available acceleration at lower velocities. Based on that, I’m thinking I may have misunderstood that post.
Thanks.